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How many computers? In a simple random sample of 150 households, the sample mean number of...
How many computers? In a simple random sample of 185 households, the sample mean number of...
How many computers? In a simple random sample of 185 households, the sample mean number of personal computer ls was 1.64. assume the population of the standard deviation is 0.47 a) construct a 99.9% confidence interval for the mean number of personal computers. round the answer to at least two decimal places. a 99.9% confidence interval for the mean number of personal computers is ---< mean <----- 2) In a sample of 75 clamps, the mean step to complete this...
In a simple random sample of 150 households, the mean number of computers was 2.13. Assume...
In a simple random sample of 150 households, the mean number of computers was 2.13. Assume the population standard deviation is σ = 0.45. Construct a 95% confidence interval for the mean number of computers.
in a simple random sample of 190 households, the sample mean number of personal computers was...
in a simple random sample of 190 households, the sample mean number of personal computers was 2.78. assume the population standard deviation is 0.41. a) a 99.8% confidence interval for the mean number of personal computers is ----< mean <----- 2) a simple random sample of eight college freshman were asked about how many hours of sleep they typically got per night. the results were 7.5, 8, 6.5, 24, 8.5, 6.5, 7, 7.5 a) the data contains an outlier that...
In a simple random sample of 64 households, the sample mean number of personal computers was 1.17. Assume the population standard deviation is σ = 0.23. 19) Why can we say the sampling distribution of...
In a simple random sample of 64 households, the sample mean number of personal computers was 1.17. Assume the population standard deviation is σ = 0.23. 19) Why can we say the sampling distribution of the sample mean number of personal computers is approximately normal? 20) Construct a 98% confidence interval for the mean number of personal computers. Interpret this interval. 21) The population standard deviation for the height of high school basketball players is three inches. If we want...
A simple random sample of 60 items resulted in a sample mean of 80. The population...
A simple random sample of 60 items resulted in a sample mean of 80. The population standard deviation is σ =15 . a. Compute the 95% confidence interval for the population mean. Round your answers to one decimal place. ( , ) b. Assume that the same sample mean was obtained from a sample of 120 items. Provide a 95% confidence interval for the population mean. Round your answers to two decimal places. ( , )
A simple random sample of 60 items resulted in a sample mean of 80
A simple random sample of 60 items resulted in a sample mean of 80. The population standard deviation is σ=15. a. Compute the 95% confidence interval for the population mean. Round your answers to one decimal place b. Assume that the same sample mean was obtained from a sample of 120 items. Provide a 95% confidence interval for the population mean. Round your answers to two decimal places c. What is the effect of a larger sample size on the interval estimate?
simple random sample of size n= 40 is drawn from a population. The sample mean is...
simple random sample of size n= 40 is drawn from a population. The sample mean is found population mean. be x 120.6 and the sample standard deviation is found to be s 12.6. Construct a 99% confidence interval for the The lower bound is (Round to two decimal places as needed.)
A random sample of 24 observations is used to estimate the population mean. The sample mean...
A random sample of 24 observations is used to estimate the population mean. The sample mean and the sample standard deviation are calculated as 128.4 and 26.80, respectively. Assume that the population is normally distributed. [You may find it useful to reference the t table.) a. Construct the 95% confidence interval for the population mean. (Round intermediate calculations to at least 4 decimal places. Round "t" value to 3 decimal places and final answers to 2 decimal places.) Confidence interval...
A random sample of 49 observations is used to estimate the population variance. The sample mean a...
A random sample of 49 observations is used to estimate the population variance. The sample mean and sample standard deviation are calculated as 59 and 3.1, respectively. Assume that the population is normally distributed. (You may find it useful to reference the appropriate table: chi-square table or F table) a. Construct the 90% interval estimate for the population variance. (Round intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.) Confidence interval b. Construct the...
A simple random sample of size n=40 is drawn from a population. The sample mean is...
A simple random sample of size n=40 is drawn from a population. The sample mean is found to be x overbar equals 120.7 and the sample standard deviation is found to be s=12.1. Construct a 99% confidence interval for the population mean. The lower bound is ________ (Round to two decimal places as needed.) The upper bound is ________ (Round to two decimal places as needed.)
simple random sample of size n= 40 is drawn from a population. The sample mean is found population mean. be x 120.6 and the sample standard deviation is found to be s 12.6. Construct a 99% confidence interval for the The lower bound is (Round to two decimal places as needed.)
A random sample of 24 observations is used to estimate the population mean. The sample mean and the sample standard deviation are calculated as 128.4 and 26.80, respectively. Assume that the population is normally distributed. [You may find it useful to reference the t table.) a. Construct the 95% confidence interval for the population mean. (Round intermediate calculations to at least 4 decimal places. Round "t" value to 3 decimal places and final answers to 2 decimal places.) Confidence interval...
A random sample of 49 observations is used to estimate the population variance. The sample mean and sample standard deviation are calculated as 59 and 3.1, respectively. Assume that the population is normally distributed. (You may find it useful to reference the appropriate table: chi-square table or F table) a. Construct the 90% interval estimate for the population variance. (Round intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.) Confidence interval b. Construct the...
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