Question

2. Solve dc dt dy dt dc + 2 dy dt = 0 dt subject to (0) = 0, y(0) = 0

Answer 1

2 dy de =et at dx differential equation. + 2 ay be the system of = dt dt NOW write me this da dt dy = et dt da + 2 dy dt dt suba tract eanation @ from then we get da dt Auto ) - (de la +2 et dt an) = et -3 dn=et dy=-13 say=J-1 et at y=-1/3 ette e be mitegratin constant put yo=0 then,

te te n w/ eo wh das bet [eºzd). and get e the sountion y = so 3 Wh then dy put dy - bet on -الن dt t e =o da dt w/N UN हो et at de = 2 et s dx =) 2 / => x= 2/3 et tk => k be integrating constant then put X0 =0 3 e tk => K= [eo=d 22%3 so the solution is get- r therefore the A is solution of the system of eacuation X(t)= et-2 / 2(+) =- et + 1/3