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Show all necessary equations or conversion factors. e. Sodium acetate and acetic acid are combined together...
In the following questions write your answers with the detailed steps. Show all necessary equations or conversion factors. a. 4.50 g sample of glucose (C6H12O6) is dissolved in enough water to make 10.0 mL of solution. Calculate the molarity. b. 424 g of solute is dissolved in enough water to give 1.00 L of solution. The density of the resulting solution is 1.18 g/mL. What is the %(w/w)? c. Write a reaction equation that corresponds to the following equilibrium expression:...
In the following questions write your answers with the detailed steps. Show all necessary equations or conversion factors. a. 4.50 g sample of glucose (C6H1206) is dissolved in enough water to make 10.0 mL of solution. Calculate the molarity. b. 424 g of solute is dissolved in enough water to give 1.00 L of solution. The density of the resulting solution is 1.18 g/mL. What is the %(w/w)? c. Write a reaction equation that corresponds to the following equilibrium expression:...
in the following questions write
your answers with detailed steps.
In the following questions write your answers with the detailed steps. Show all necessary equations or conversion factors. a. 4.50 g sample of glucose (C6H120) is dissolved in enough water to make 10.0 mL of solution. Calculate the molarity. b. 424g of solute is dissolved in enough water to give 1.00 L of solution. The density of the resulting solution is 1.18 g/mL. What is the %(w/w)? c. Write a...
You are making a pH 5.0 buffer with acetic acid (pKa = 4.75) and sodium acetate. You want the total concentration of acetate ([acetic acid] + [sodium acetate] ), to be 0.50 M. What concentrations of acetic acid and sodium acetate do you use to make your buffer? acetic acid sodium acetate
Acetic acid has a pKa of 4.74. A stock solution of 1.0 M acetic acid is available. A stock solution of 2.0 M potassium acetate is available. Show all the calculations and explain how to make 560.0 mL of 250. mM acetate buffer that has a pH = 5.0. (Hint: first make a 250 mM potassium acetate solution and a 250 mM acetic acid solution. Then determine how much of each to use.). pH = pKa + log {[acetate]/[acetic acid]}
Acetic acid and its conjugate base acetate can form an acid-base buffer. The pKa of acetic acid is 4.75. How much 10.0 M HNO3 must be added to 1.00 L of a buffer that is 0.0100 M acetic acid and 0.100 M sodium acetate to reduce the pH to 4.90 ? ___mL?
For a buffer made from sodium acetate and acetic acid, the Ka of acetic acid is 1.8E-5. What mass of sodium acetate (NaCH3CO2) must be added to 2.50 L of 0.68 M acetic acid to make a buffer solution with pH = 5.75? The answer should be in two significant figures.
For acetic acid pKa =4.74. A buffer solution was made using 0.30 mole of acetic acid and an unspecified and amount of sodium acetatein water to make 2.00 liters of solution. The solution pH was 4.91. Calculate the number of moles of sodium acetate used.
Prepare 100mL of a 0.2M acetate buffer solution of pH =4.76 (using 17.6N acetic acid and sodium acetate). a. Calculate the volume of acetic acid and weight of sodium acetate necessary to prepare the buffer solution. pKa of acetic acid is 4.76
Acetic acid and its conjugate base acetate can form an acid-base buffer. The pKa of acetic acid is 4.75. 1st attempt FeedbackSee HintSee Periodic Table How much 10.0 M HNO3 must be added to 1.00 L of a buffer that is 0.0100 M acetic acid and 0.100 M sodium acetate to reduce the pH to 5.05 ?