Question

hw help

Consider the equation exin(y)+5x +1=y? Find dy dx in terms of X and y. Evaluate dx at (x,y) = (0,1). Select the correct answer. -5 5 ООО 2

Answer 1

I have used the product rule for differentiability,also the chain rule and implicite rule of differentiation. I hope you like this.

2 بکر o equation elny) +5%+" = Differentiating with respect to exfen(y)) t en n, weget ly dy t 5 ay ay da dy cla Lex -Y dy cha 2 - (e? (ny)+5) - [enkin y) +5] en 24 at (hy)= (0,1), dy dä -5 le ln(2) ts) e - 2.1 5 (0.1) 1-2 Ansuar @ 3 x y 2 x²y + y² + 14 then differentiating with respect to x, 3 x 24 dy + 372 x² dy +227 + 27 dy we get da da da 2 3). dy dae [6 xy = x² - x²-28 2xy = 34 dy. du Answer 36-9-6 32 dy + 37 dy (2x-32 ta Gay -n²-27 at x=3722, 266-6). e37% = x² + y ² - 4 Differentiating with respect to it, we get exy det dy 32 exy -2y ct 830.92,07 on the e 5, de [ 0-4] Geox5 ay you - Answer dx It = 21 dx + 27 du lat at 7) [ 3 21 de at - 37e3*7 dt when - 30 -30 V! 15 2