2x+2y=0
y=1
Therefore,
Substituting y=1 in the given equation,
2x+2(1)=0
2x+2=0
2x=-2
x=-2/2
x=-1
y" + 2y' = 2x + 5 - e-2x
Solve 3x + 2y – z = 1x – 2y + z = 02x + y – 3z = -1
Solve using Cramer's Rule X – 2y +z=7 2x +y – z=0 3x + 2y – 2z = -2 O (1,-2,0) O (2,-1,3) O (1,-1,1) No Solution
Find a solution 10. y" – 2y' + 2y = 2x, y(0) = 4, y'0) = 8.
Show all work for each problem. 1. (15 pts) y"-2y'+2y = 2x, y(0) = 4, y"0) = 8, y, =ce" cosx+c,e' sin x, y, = x+1. Find a solution satisfying the given initial conditions.
Using matrices to solve systems of equations 1. 2x- 3/2y=-9 2x+y=-4
1. Solve the following differential equations: a. xy'=y+Vxy x+2y+3 y'= b. 2x – y +5 x+2y+3 y'= x+2y+5 y cos(x+y)+x+y d. sin(x + y) + y cos(x+y)+x+y C. y'=
Systems of Equations: 3x + y = 6 2x-2y=4 Substitution: Elimination: Solve 1 equation for 1 variable. Find opposite coefficients for 1 variable. Rearrange. Multiply equation(s) by constant(s). Plug into 2nd equation Add equations together (lose 1 variable). Solve for the other variable. Solve for variable. Then plug answer back into an original equation to solve for the 2nd variable. y = 6 -- 3x solve 1" equation for y 6x +2y = 12 multiply 1" equation by 2 2x...
Solve this system of a linear equation. 2x + y = 1 4x +2y = 3
7. Given that y(x) = sin 2x is a particular solution to y" + 2y + 4y - 4 cos 2x = 0, find the general solution.