Homework Answers
O 1.8 Question 4 1 pts Planet X has a mass of 6.39 1023 kg and...
O 1.8 Question 4 1 pts Planet X has a mass of 6.39 1023 kg and it orbits 2.08 x 108 km from a star with a period of 687 days. What is the angular momentum of the planet around its star? Answer in units of kg m2/sec. Due to its large distance from its star, you can treat the planet as a point mass in its circular motion around the star. O 1.61 x 1039 O 2.93 x 1039...
Planet X has a mass of 4.86 x 102 kg and it orbits 1.09 x 108...
Planet X has a mass of 4.86 x 102 kg and it orbits 1.09 x 108 km from a star with a period of 225 days. What is the angular momentum of the planet around its star? Answer in units of kg m²/sec. Due to its large distance from its star, you can treat the planet as a point mass in its circular motion around the star. O 1.86 x 1040 O 1.61 x 1039 O 2.93 x 1039 O...
A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x...
A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x 1030 kg. Consider the orbit of the planet to be circular Ind the star is at the center. The distance between the star and the planet is 1.496 x 1011 m. Calculate the orbital velocity of the planet. (G= 6.67x10-11 m3 kg-152) (In the choices below, 10^4 is 104)
show work! O Question 4 Planet Xhasa mass of 1.89 x 101 kg anditorbits 1.09 x...
show work!
O Question 4 Planet Xhasa mass of 1.89 x 101 kg anditorbits 1.09 x 20%km from a star witha period of 225 days What is the angular momentum of the planet around its star? Answer in units of ke msec. Due to its large distance from its star, you can treat the planet as a paint mass in its dirailar motion around the star. 020 x 10 0293 x 100 01.88x109 Olbx100 02.10 x 100
Earth has a mass of 5.97 x 1024 kg and a radius of 6.38 x 106...
Earth has a mass of 5.97 x 1024 kg and a radius of 6.38 x 106 m. Assume it is a uniform solid sphere. The distance of Earth from the sun is 1.50 x 1011 m. (Assume Earth completes a single rotation in 24.0 hours and orbits the Sun once every 365 Earth days.) (a) Calculate the angular momentum of Earth in its orbit around the Sun kg m2/s (b) Calculate the angular momentum of Earth on its axis kg...
A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x...
A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x 1030 kg. Consider the orbit of the planet to be circular and the star is at the center. The distance between the star and the planet is 1.496 x 1011 m. Calculate the orbital velocity of the planet. (G=6.67x10-11 mº kg1s 2) (In the choices below, 10^4 is 104) O 2.99 x 10^4 m/s 8.92 x 10^4 m/s O 4.58 x 10^4 m/s O...
Planet M has a mass if 4.86x10^24 kg and it orbits 1.09x10^8 km from a star...
Planet M has a mass if 4.86x10^24 kg and it orbits 1.09x10^8 km from a star with a period of 225 days. What is the angular momentum if the olant around its star? Answe in kg m^2/sec
Planet X of mass mx = 6.3 × 1024 kg orbits S in uniform circular motion...
Planet X of mass mx = 6.3 × 1024 kg orbits
S in uniform circular motion at a distance rx and with a
period Px = 1.5 years (=4.7304 × 107 s). The
mass of the star S is MS = 2 × 1031
kg and its radius is RS = 4.2 × 108 m, as
shown in the figure.
1) What is rx, the orbital radius of Planet X around
the Sun?
a) rx = 4.21 × 109 m...
The Earth has a mass of 5.97 * 1024 kg and the Sun has a mass...
The Earth has a mass of 5.97 * 1024 kg and the Sun has a mass of 2.00 * 1030 kg. If they are separated by a distance of 1.50 * 108 km, what is the force (in N) between the Earth and the Sun? Answer in Sci Notation. Then, assuming the Earth travels in a perfect circle around the Sun, with masses and distances given above, and takes 365.25 days to complete a complete circle. What is the centripetal...
A planet of mass m = 1.55 x 1024 kg is orbiting in a circular path...
A planet of mass m = 1.55 x 1024 kg is orbiting in a circular path a star of mass M = 9.75 x 1029 kg. The radius of the orbit is R = 4.65 x 107 km. What is the orbital period (in earth days) of the planet? Where G = 6.67 � 10-11 N�m2/kg2 and 1 day = 8.54 � 104 s. I used the formula and got T = 247 s = 0.0289 days, but the online...
O 1.8 Question 4 1 pts Planet X has a mass of 6.39 1023 kg and it orbits 2.08 x 108 km from a star with a period of 687 days. What is the angular momentum of the planet around its star? Answer in units of kg m2/sec. Due to its large distance from its star, you can treat the planet as a point mass in its circular motion around the star. O 1.61 x 1039 O 2.93 x 1039...
Planet X has a mass of 4.86 x 102 kg and it orbits 1.09 x 108 km from a star with a period of 225 days. What is the angular momentum of the planet around its star? Answer in units of kg m²/sec. Due to its large distance from its star, you can treat the planet as a point mass in its circular motion around the star. O 1.86 x 1040 O 1.61 x 1039 O 2.93 x 1039 O...
A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x 1030 kg. Consider the orbit of the planet to be circular Ind the star is at the center. The distance between the star and the planet is 1.496 x 1011 m. Calculate the orbital velocity of the planet. (G= 6.67x10-11 m3 kg-152) (In the choices below, 10^4 is 104)
show work!
O Question 4 Planet Xhasa mass of 1.89 x 101 kg anditorbits 1.09 x 20%km from a star witha period of 225 days What is the angular momentum of the planet around its star? Answer in units of ke msec. Due to its large distance from its star, you can treat the planet as a paint mass in its dirailar motion around the star. 020 x 10 0293 x 100 01.88x109 Olbx100 02.10 x 100
Earth has a mass of 5.97 x 1024 kg and a radius of 6.38 x 106 m. Assume it is a uniform solid sphere. The distance of Earth from the sun is 1.50 x 1011 m. (Assume Earth completes a single rotation in 24.0 hours and orbits the Sun once every 365 Earth days.) (a) Calculate the angular momentum of Earth in its orbit around the Sun kg m2/s (b) Calculate the angular momentum of Earth on its axis kg...
A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x 1030 kg. Consider the orbit of the planet to be circular and the star is at the center. The distance between the star and the planet is 1.496 x 1011 m. Calculate the orbital velocity of the planet. (G=6.67x10-11 mº kg1s 2) (In the choices below, 10^4 is 104) O 2.99 x 10^4 m/s 8.92 x 10^4 m/s O 4.58 x 10^4 m/s O...
Planet X of mass mx = 6.3 × 1024 kg orbits
S in uniform circular motion at a distance rx and with a
period Px = 1.5 years (=4.7304 × 107 s). The
mass of the star S is MS = 2 × 1031
kg and its radius is RS = 4.2 × 108 m, as
shown in the figure.
1) What is rx, the orbital radius of Planet X around
the Sun?
a) rx = 4.21 × 109 m...
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