Question

At a certain airport, 80% of the flights arrive on time. A sample of 14 flights is studied. 1) Find the probability that 9 fl
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Answer #1

Let X be number of flights on time.

X follows Binomial distribution with parameters; sample size = n = 14 and probability of flights arrive in time = P = 0.8

Hence,

P(X=x) = nCx * P^x *(1-P)^(n-x)

1.

Probability that 9 flights were on time

P(X = 9) = 14C9 * 0.8^9 * (1-0.8)^(14-9)

P(X = 9) = 0.0860

2.

Probability that 10 flights were on time

P(X = 10) = 14C10 * 0.8^10 * (1-0.8)^(14-10)

P(X = 10) = 0.1720

3.

Probability that 11 or more flights were on time

= P(X>=11)

= P(X=11) + P(X=12) + P(X=13) + P(X=14)

= 14C11 * 0.8^11 * (1-0.8)^(14-11)

+ 14C12 * 0.8^12* (1-0.8)^(14-12)

+ 14C13 * 0.8^13 * (1-0.8)^(14-13)

+ 14C14 * 0.8^14 * (1-0.8)^(14-14)

= 0.6982

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