An object 3.75 cm tall stands 20.0 cm in front of a diverging lens of focal...

Question

Question

An object 3.75 cm tall stands 20.0 cm in front of a diverging lens of focal length magnitude 15.0 cm. a) Find the image dista

Answer 1

Answer #1

tho = 3.75 cm, do = 20cm, f = -15cm @ + do di 0 20 Itt 21 di -15 -12-20-15-35 di 15 20 (15) (20) di = -500 z -8.57cm 300 Aue

Part c) Image is Virtual because image distance that is di is negative as calculated in part a

Part d) Image is Erect because height of image that is hi is positive as calculated in part b

Hope this helps...

Answer 2

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