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E Question Help Consider a drug testing company that provides a test for marijuana usage. Among 301 tested subjects, results from 25 subjects were wrong (either a faise positive or a false negative). Use a 0.01 significance level to test the claim that loss than 10 percent of the test results are wrong. 0 C. Ho: p = 0.1 H,<0.1 OD HD 0.1 H,:p>0.1 Library Identify the test statistic for this hypothesis test. a hide contes The test statistic for this hypothesis testis (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test atents Resources access O A. Fail to reject Hy. There is sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong. OB. Fail to reject H, There is not sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong. OC. Reject Hy. There is not sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong. OD. Reject H. There is sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong. Options ols

Answer 1

Solution : biven that Sample size (n) = 301 sample proportion (8) = 25 0.083 301 The hall hapothesis is : Ho: P = 0.10 The allernative hypothesay jis: Hip 20.10 P-P The Z-test satatistic : 2= PC-pa) n 0.083-010 -0.017 2= -0.9832 0:10 (1-0-10) 0.01729 301 Z = -0.9832 P-vallee = p<<-0.9832) = 0.1628 P-value = 0.163 The P-value is greater than the 1% level of significance. we fail to reject Ho. There is not sufficient evidence to warrent support of the cabin that less than 10% of the test results are wrong

2 birch that, Sample size(n) 2219 Sample proportion (P) = 81-7%.=0.817 The heeld and alternative hoypotheses are: Hi p=0.8 H:P #0:8 The test statistic is: z= P- P-P P (1-P) 0-817-0.8 0.017 = = 0.6296 0.8(1-0-8) 0.0270 219 The test stehistic is: 12 = 0.63 P-value = P(Z40-63) =0.7357 P-value =0.736 The P-value is greater than 0.10 significance level we fail to reject to. There is not sufficient evidence to reject the celeim that 80% of patients stop smoking when given sustained care.