Determine the inverse Laplace transform of the function below 6s 52 + 25 Click here to view the table of Laplace transforms. Click here to view the table of properties of Laplace transforms. e 6s L-1 s2 + 25 >(t) =
Find the inverse Laplace transform a . 3 s4 - 2s s2 (3s2 + 4) 3 S4 – 25 (s + 1)(3s2 + 4s + 2) b.
Determine the inverse Laplace transform of the function below. 2s + 36 s? +65 +34 L II 1__25+ 36 + 6s +34) 2
Find the inverse Laplace transformation of: a) F(s)- b) F,(s)--2 c) F(s) = 2,242 4 s2+6s +5 s2 +3s +1 3+2s+s s2 +9s +18 e) F(s)--一5 2s4 +12s+90 (s+2)(s +2s+2)
3. Use method of residues to calculate inverse Laplace Transform of the following: s4-2s+1 s2 (s2+4) s2-2s+1 a) X(s (b) X(s) = (s+2)2+4
find. inverse Laplace transfer show step buy step soultion +8 (b) s(+16) 2s3 3s +6s+4 (s2 +4)(s2 +2s+2) (c) +3s + (d) 2 2 1 s-2s +s (e) (s+2)e (f 2s +1 22-6s3 (g) -3s +2 2(s22r4) (24) (h) 2 (i) (2s+1 ($2+8)e (i) (216) +8 (b) s(+16) 2s3 3s +6s+4 (s2 +4)(s2 +2s+2) (c) +3s + (d) 2 2 1 s-2s +s (e) (s+2)e (f 2s +1 22-6s3 (g) -3s +2 2(s22r4) (24) (h) 2 (i) (2s+1 ($2+8)e (i)...
Determine the inverse Laplace transform of the function below. Se - 2s S2 + 8s +32 Click here to view the table of Laplace transforms. Click here to view the table of properties of Laplace transforms. - 2s Se - 1 >(t) = $2 +85 +32 (Use parentheses to clearly denote the argument of each function.)
Find the Laplace Transform for each of the following: 1. L{2sin x + 3e0s 22}= (W) *** ** (m 3 to the (s? +1)(s2 + 4) 2. 1{eosusa)= ) og 2 ( 6+23+25 ( 6+2+25 2s ZS 3. Find the inverse Laplace Transform L'{- S +1 (4) tsint (B) ’sint (0) (D) rcost
8. Find the inverse Laplace transform L-{F} for F below (hint: complete the square). F(S) S + 10 S2 – 6s + 34
9s 11 (1 pt) Find the inverse Laplace transform f(t) = L=1 {F(s)}| of the function F(s) s2 2s5 9s 11 f(t)= L' help (formulas) $2-2S+5