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Question 2. (15 pts) Let vi= (-3 0 6), V2= (-2 2 317, V3= [0 - 6 3), and w=(1 14 9) (1). Determine if w is in the subspace
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Answer #1

Q. 2. Let A = [v1,v2,v3,w] =

-3

-2

0

1

0

2

-6

14

6

3

3

9

To determine whether w is in the subspace spanned by v1,v2,v3 and whether v1,v2,v3 are linearly independent , we will reduce A to its RREF as under:

Multiply the 1st row by -1/3

Add -6 times the 1st row to the 3rd row

Multiply the 2nd row by 1/2

Add 1 times the 2nd row to the 3rd row

Multiply the 3rd row by 1/18

Add -7 times the 3rd row to the 2nd row

Add 1/3 times the 3rd row to the 1st row

Add -2/3 times the 2nd row to the 1st row

Then the RREF of A is

1

0

2

0

0

1

-3

0

0

0

0

1

sThis implies that:

(1). w cannot be expressed as a linear combination of v1,v2,v3 . Therefore, w is not in the subspace spanned by v1,v2,v3 .

(2). The vectors v1,v2,v3 are not linearly independent as v3 = 2v1-3v2 so that 2v1-3v2 - v3 = 0

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