Delta Tf = Kf×m
m is molality
Kf is is constant
Delta Tf=4.68×85×1000/154×750
Delta Tf=3.44
-63.5-Tf =3.44
Tf=-66.94 degree Celsius
The answer is -66.9
please answer ASAP Kf for chloroform is 4.68 °C/m; normal freezing point of chloroform is -63.5°C....
Kf for chloroform is 4.68 C/m: normal freezing point go chloroform is -63.5 C. Calculate the freezing point of a solution containing 750 g of chloroform CHCL3 and 85 g of a solute that has a molar mass of 154 g/mol..
Calculate the Freezing point of a solution containing 0.6 kg of chloroform, CHCL3, and 42.0 g of eucalptol, C10H18O. the normal freezing point of cholorform is (-63.5 c ) and the Kf IS 4.68 c/m
Molal Boiling-Point-Elevation and Freezing-Point-Depression Solvent Normal Boiling Point (∘C) Kb (∘C/m) Normal Freezing Point (∘C) Kf (∘C/m) Water, H2O 100.0 0.51 0.0 1.86 Benzene, C6H6 80.1 2.53 5.5 5.12 Ethanol, C2H5OH 78.4 1.22 -114.6 1.99 Carbon tetrachloride, CCl4 76.8 5.02 -22.3 29.8 Chloroform, CHCl3 61.2 3.63 -63.5 4.68 Part E freezing point of 2.02 g KBr and 4.84 g glucose (C6H12O6) in 187 g of water Part F boiling point of 2.02 g KBr and 4.84 g glucose (C6H12O6) in...
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