Question

The decomposition of dinitrogen pentoxide is described by the chemical equation 2N05(9) + 4NO2(g) + O2(9). If the rate of appearance of NO is equal to 0.860 mol min" at a particular moment, what is the rate of appearance of O2 at that moment? 0.430 mol min1 O 0.215 mol min-1 O 1.72 mol min1 O 3.44 mol min?

Answer 1

2N205 (9) rate do apperance of No₂ solution described De Composition of chemical cauation dinitrogen by chemical Pentonide is 4NO2 (9) + O₂(g) If rate to apperance do No2 0.860 mol-min at a particular moment. NO2 is eaual to from chemical equation Instantaneous nate - - 1 / 2 at d [N205] = +1 + 1 d [Na [02] - u at td at i-e = 0.860 mol.mint td dt [NO2] = 0.860 mol mint From expression ① td [NO2 4 at td [02 de - (0.860) molmint 4 = +d [02 td [02 at 0.215 mol mint at

+d de [0₂] 0.215 mol mint Rate of apperance & ₂ = 0.215 mol mint