load is assumed to be point load P =62 KN at the centre
now this is reduced to case of simply supported beam with point load at centre
now Maximum Bending moment = P*length of neam/4 = 62*4/4 = 62 KNm
now maximum allowable bending stress = Max moment /Section modulus
150*106 = 62*103/Section modulus
Section modulus = 4.13333 * 10-4 m3 = 413.333 mm3 Ans
Calculate the section modulus of the beam shown below if P-a62N it the allowable rormal stressors...
Calculate the section modulus of the beam shown below if Pmax = 45 kN if the allowable normal stress o allow = 150 MPa and an allowable shear stress, Tallow 85 MPa. Write your answer in mm2 to 2 decimal places. -2 m 2 m P
In the design of the beam shown below, the shear stress is to be found in MPa. Calculate the shear stress to 2 decimal places of the beam below given allowable shear stress Tallow = 85 MPa and the W-section is made with d=313 mm and tw=6.6 mm. -2 m- 2 m P
In the design of the beam shown below, the shear stress is to be found in MPa. Calculate the shear stress to 2 decimal places of the beam below given allowable shear stress Tallow = 85 MPa and the W-section is made with d=313 mm and tw=6.6 mm. -2 m 2 m
The cantilevered beam shown below is a sandwich beam with a plastic core and aluminum alloy faces. The member is subjected to a concentrated load at the free end. The plastic core (240mm x 200 m m in cross section) has an elastic modulus of 100 GPa and allowable normal stress of 220 MPa, while the 6 mm thick aluminum face plates have an elastic modulus of 75 GPa and allowable normal stress of 260 MPa. Question I: 118 marks]...
The beam has the triangular cross section shown. The allowable stress in bending is 150 MPa. Determine the largest allowed uniform distributed load w. 6 m 300 mm 150 mm
Design the cantilever beam below to take the maximum load. Calculate the load in KN to 2 decimal places, if the allowable bending stress is allow = 162 MPa and the allowable shear stress is Tallow = 95 MPa. Also I = 11.918 x 10-6 m4 and the y_bar = 0.04875 m from the top of the t-beam. 150 mm 15 mm T150 mm Hi 15 mm P P 2 m 2 m
QUESTION 11 Knowing that for the extruded beam shown in the figure below, the allowable stress is 120 MPa in tension and 150 MPa in compression. 125 mm N-A 50 mm 125 mm 150 mm The centroid () measured from bottom of cross-section is: [mm.] 114.7 138.25 151.32 163.17 NI QUESTION 12 The moment of inertia () around neutral axis (N.A.) is: [m 122.16x 10 5 165.56x 10 5 212.45x 10 6 310.11x 10 5
The built-up beam is made of steel as shown in Figure 1. Knowing that modulus of elasticity for the steel is E = 200 GPa 150 mm 20 mm 150 mm 150 mm 10 mm M '10 mm 300 mm А Figure 1 (1) If the allowable tensile and compressive stress for the beam are allow tension = 140 MPa and o = 210 MPa. allow compression respectively, determine the maximum allowable internal moment M that can be applied Determine...
For the beam and loading shown, design the cross section of the beam, knowing that the grade of timber used has an allowable normal stress of 11.5 MPa. (Round the final answer to one decimal place.) 1.8 kN 3.6 KN 40 mm 0.8 m 0.8 m 0.8 m The height h of the beam is mm.
PROBLEM 3 Knowing that for the cantilever beam shown in Figure 3, the allowable stress is 120 MPa in tension and 150 MPa in compression, determine the largest couple M that can be applied. Figure 3 (b) Section a-a (dimension not to scale) "Х Figure 3(c) 610UB125 Figure 3(d) 300PFC dt(X10s yo section | x | y (x106 2 mm 986 72.4 610UB125 1600022961219.6 11.9 5110 90 300 16 39.3 4.04 300PFC 24.1 Figure 3 (a)Cantilever beam 300PFC 610UB125 Figure...