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V1 = 8 m/s V2 = 4 m/s Vi' = ? v2 = 7 m/s OW...
V1 = 8 m/s V2 = 4 m/s Vi' = ? v2 = 7 m/s OW m1 m2 mi m2 In the above collision what is va'? Question 7 8 pt [Continued from Question 6.] If my = 350 g what is m2?
[The following diagram is for Questions 6-7.] V1 = 8 m/s v2 = 4 m/s Vi'...
[The following diagram is for Questions 6-7.] V1 = 8 m/s v2 = 4 m/s Vi' = ? v = 7 m/s m1 m2 POW mi m2 In the above collision what is val? O 5 m/s O 1 m/s 0-1 m/s 4 m/s 0 -3 m/s O 2 m/s 0-4 m/s -8 m/s 0-5 m/s 8 m/s 3 m/s 2 m/s Question 7 8 pts [Continued from Question 6.) Ifm - 350 g what is m2? O 2.3 kg...
Part e: Elastic Collision mi 35 m 35 m 2 mi r=.5 m m2 m2 V2...
Part e: Elastic Collision mi 35 m 35 m 2 mi r=.5 m m2 m2 V2 .5 m Theoretical: For an elastic collision between two obiects with equal masses, ? + ?,-90° Find the vi and v2 after the collision Experimental: Set up in IP Set elastic to 1 for both masses. Set friction to be zero Find vi, V2, and % error
Eqation: 2I^-(aq) + 2NO2^-(aq) + 4H^+(aq) ---> I2(aq) + 2NO(aq) + 2H2O(l) 1. MI*V1 - M2*V2...
Eqation: 2I^-(aq) + 2NO2^-(aq) + 4H^+(aq) ---> I2(aq) + 2NO(aq)
+ 2H2O(l)
1. MI*V1 - M2*V2 V2 - 10ml VI = 2ml 4.5. 2 - M2 * 10 M2 - 0.9mM 2. Ksp - [Pb 2+][-]^2 Ksp - 1.401008 1.4*10^-8 - [Pb 2+1 (1.1 10.47 2 [Pb 2+] - 1.16M 3. Examine Eq. 3, above. Is this a redox reaction? If so, which element is being oxidized? Which element is being reduced? Explain your answer(s) by using the appropriate oxidation...
Object 1 has a mass mi and a velocity v1 = (2.20 m/s )*. Object 2...
Object 1 has a mass mi and a velocity v1 = (2.20 m/s )*. Object 2 has a mass m2 and a velocity v2 = (3.30 m/s ý. The total momentum of these two objects has a magnitude of 20.0 kg. m/s and points in a direction 70.0° above the positive o axis. You may want to review (Pages 258 - 259). Part A Find mi. VO AED ? PER m = kg Submit Request Answer Part B Find m2...
A block of mass mi 1.60 kg moving at v1 2.00 m/s undergoes a completely inelastic...
A block of mass mi 1.60 kg moving at v1 2.00 m/s undergoes a completely inelastic collision with a Part A telLionary block of mass m = 0.600 kg. The blocks time, the two-block system collides inelastically with a third block, of mass m3 = 2.50 kg , which is initially at rest. The three blocks then move, stuck together, with speed u3.(Figure 1) Assume that the blocks slide without friction. Find the ratio of the velocity v2 of the...
Find V1 and V2 4 Ω . 2Α 4Ω s * V2 Vi 1Ω 2i, -...
Find V1 and V2
4 Ω . 2Α 4Ω s * V2 Vi 1Ω 2i, - 2 Ω + 10 V
Two blocks have masses mi = 5 kg and m2 = 1 kg and speeds v1...
Two blocks have masses mi = 5 kg and m2 = 1 kg and speeds v1 = 2 m/s and v2 = 5 m/s. The objects slide directly toward each other along a frictionless horizontal surface and collide. After the collision, block mi is at rest. (Hint: impulse, linear momentum conservation) a. What is the magnitude of the impulse, Jil, exerted on block mı during the collision? b. What is the magnitude of the impulse, 1J21, exerted on block me...
Anyone please help me solve the last part to find theortetical of V1 and V2 using the first page ...
anyone please help me solve the last part to find theortetical
of V1 and V2 using the first page type of collision
thank you
4. Cartl has a mass of ml and a velocity of v0. Cart2 has a mass of m2 and is stationary. Cartl then hits cart 2. After the collision, the velocity of cartl is vl and the velocity of cart2 is v2. In any collision, what happens to the m Write an equation for the momentum...
Consider two masses sliding across a frictionless surface about to undergo a head-on collision as shown...
Consider two masses sliding across a frictionless surface about to undergo a head-on collision as shown in the figure. The first mass (m1 =3 kg) is travelling to the right with a speed of v1 = 8 m/s. The speed of the second mass (m2 = 5 kg) is unknown. After the masses collide, ma rebounds moving off at a speed of v = 2 m/s in the opposite direction, while mz is motionless. a)(10 pts.) At what velocity, v2...
V1 = 8 m/s V2 = 4 m/s Vi' = ? v2 = 7 m/s OW m1 m2 mi m2 In the above collision what is va'? Question 7 8 pt [Continued from Question 6.] If my = 350 g what is m2?
[The following diagram is for Questions 6-7.] V1 = 8 m/s v2 = 4 m/s Vi' = ? v = 7 m/s m1 m2 POW mi m2 In the above collision what is val? O 5 m/s O 1 m/s 0-1 m/s 4 m/s 0 -3 m/s O 2 m/s 0-4 m/s -8 m/s 0-5 m/s 8 m/s 3 m/s 2 m/s Question 7 8 pts [Continued from Question 6.) Ifm - 350 g what is m2? O 2.3 kg...
Part e: Elastic Collision mi 35 m 35 m 2 mi r=.5 m m2 m2 V2 .5 m Theoretical: For an elastic collision between two obiects with equal masses, ? + ?,-90° Find the vi and v2 after the collision Experimental: Set up in IP Set elastic to 1 for both masses. Set friction to be zero Find vi, V2, and % error
Eqation: 2I^-(aq) + 2NO2^-(aq) + 4H^+(aq) ---> I2(aq) + 2NO(aq)
+ 2H2O(l)
1. MI*V1 - M2*V2 V2 - 10ml VI = 2ml 4.5. 2 - M2 * 10 M2 - 0.9mM 2. Ksp - [Pb 2+][-]^2 Ksp - 1.401008 1.4*10^-8 - [Pb 2+1 (1.1 10.47 2 [Pb 2+] - 1.16M 3. Examine Eq. 3, above. Is this a redox reaction? If so, which element is being oxidized? Which element is being reduced? Explain your answer(s) by using the appropriate oxidation...
Object 1 has a mass mi and a velocity v1 = (2.20 m/s )*. Object 2 has a mass m2 and a velocity v2 = (3.30 m/s ý. The total momentum of these two objects has a magnitude of 20.0 kg. m/s and points in a direction 70.0° above the positive o axis. You may want to review (Pages 258 - 259). Part A Find mi. VO AED ? PER m = kg Submit Request Answer Part B Find m2...
A block of mass mi 1.60 kg moving at v1 2.00 m/s undergoes a completely inelastic collision with a Part A telLionary block of mass m = 0.600 kg. The blocks time, the two-block system collides inelastically with a third block, of mass m3 = 2.50 kg , which is initially at rest. The three blocks then move, stuck together, with speed u3.(Figure 1) Assume that the blocks slide without friction. Find the ratio of the velocity v2 of the...
Find V1 and V2
4 Ω . 2Α 4Ω s * V2 Vi 1Ω 2i, - 2 Ω + 10 V
Two blocks have masses mi = 5 kg and m2 = 1 kg and speeds v1 = 2 m/s and v2 = 5 m/s. The objects slide directly toward each other along a frictionless horizontal surface and collide. After the collision, block mi is at rest. (Hint: impulse, linear momentum conservation) a. What is the magnitude of the impulse, Jil, exerted on block mı during the collision? b. What is the magnitude of the impulse, 1J21, exerted on block me...
anyone please help me solve the last part to find theortetical
of V1 and V2 using the first page type of collision
thank you
4. Cartl has a mass of ml and a velocity of v0. Cart2 has a mass of m2 and is stationary. Cartl then hits cart 2. After the collision, the velocity of cartl is vl and the velocity of cart2 is v2. In any collision, what happens to the m Write an equation for the momentum...
Consider two masses sliding across a frictionless surface about to undergo a head-on collision as shown in the figure. The first mass (m1 =3 kg) is travelling to the right with a speed of v1 = 8 m/s. The speed of the second mass (m2 = 5 kg) is unknown. After the masses collide, ma rebounds moving off at a speed of v = 2 m/s in the opposite direction, while mz is motionless. a)(10 pts.) At what velocity, v2...
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