Question

w standing electromagnetic wave in a 610 W microwave oven. The oven has a length of 0.21 m and a square cross-section of side w = 0.40 m. The electric field is shown in red and the magnetic field in blue at one instant. The standing wave has 4 nodes in the interior of the microwave and both E and go to zero at the sides. The electric field reaches its peak magnitude on the cross-sectional area, A. Take the speed of light in the oven to be c3.00 - 10 m/s Part A - What is the wavelength of the standing wave in the microwave? IMA ? 2 Value Units

Answer 1

Part-A 57 = 1 if a is the warelength then , 51 2 52 e (there are 5 half wares filling the length. e) x=21 ginen, l= 0.21m i = (2*0:24) a D 0.084 m Part-B it, f is is the frearency c is the speed of light & then Cefa fa A n

f = 3.57 1428571x100 Hz 3.1108 > f 0.084 > f = 3571428571 HZ o = 13.571428571 GHz = 3.571 GHZ (appron) E f = 3571428571 Hz = 3.571 GHz Cappoon) Part-c we know that the energy density us HIU Peak value of & if & is the electric field, then the energy density na 2 €. E? 30, 픈 { t. F? 2 I Eo - ก til

Putting ti=8.854 > 1012 ginen, Power p= 61ow is passing through area a= 0.45 m² ره و IT P A 2 P >> E. E.CA Flm ci 3+108 mis A = 0.42 m² p = Glow NIC Bos N 2x 610 8.854x1512 3x108 +(0.42 M २ > Eo = 1.694.296984 NIC IN E = 1694.297 NIC Capppon song