Question

Choose the incorrect statement Aniline undergoes Friedel-Crafts reactions. OA B. Using (1) HCI, H20, heat and (2) HO-to remove (deprotect) the acetyl group back to amino group, The amino group on aniline can be protected by acetylation step. Halogenation of benzene with a strong activating substitutent does not require FeBrz. D. Friedel-Crafts acylations will not occur if there is a meta-director already on the benzene ring. E. 000 30 М.

Answer 1

The incorrect statement is (K) Aniline undergees Frieskel- Geofte reaction Aniline can't vurdergo focicdel-Craft reaction, The lewis acid Alclo which in election deficient species reacts with lone pare of aniline _dus ΝΗ, NH + Anhydrous els (ring is is election I effect) deficient) cannot undergo Craft reaction as can't attack deficient species Freiedel electrophile electron true. aree (b), (c), (D), E) ®) depersbrali deprotection in dene done by hydralysie NAPELA JOH NH -cthy selly Hel, H2O -CH3 -NHL Jet LOH (base -Nha Protection of amino group!

Benefits etia NH2 twi © VH、 ells و اگر هم به снэ ett3 ht CH₂COOH e 1 The lone pair of N is participating with carbonyl group. In this a in conjugation Rete amino greenpois Fhotected.

S D. Hence increase the election dens in the ring. without (strong activating gresup) X2 halogenation is possible Because the the strong activating group will ensity electrophile can easily attack the ring (E) If there is a meta directing group is present, it wille always deactive the reing substitution reaction. It will decreases density. Hence Friedel Craft acylation mota directing greeup already present leweis aceda Howeveda electrophilie the election will not accue is there i he