Question

As shown in the figure below, a bullet is fired at and passes through a piece of target paper suspended by a masses string. The bullet has a mass m, a speed v before the collision with the target, and a speed (0.53er passing through the target The collision is inelastic and during the collision, the amount of energy lost is equal to a fraction ((0.26) Ecl of the kinetic energy of the bullet before the collision. Determine the mass of the target and the speed of the target the instant after the collision in terms of the mass of the bullet and speed of the bullet before the collision (Express your answers to at least 3 decimals.) V- M- m
as shown in the figure below, a bullet fired at and passed through a piece of target paper suspended by a massless string.

Answer 1

KreAC = á m(0.536 1)2 Given that Amount of Energy losk 0.263 SKEDBC KELBC mua KEPAC = 言M2 Difference in Energies. Kinckic Energy Lost [amut įm (0.536v)27- Cá mwa] - 0.263xgmva MV - Āmuz (-0.5362++0.236) MV2 = 0.9487 m2 +0 Momenkum remains Conserved, mw = mC0.536V) + MV -> MV- 0.464 m (0.46 You) V = 0.9487 mwa N = 2.044 0 0 M (2.0440)² = 0.9487 m2 M = 0.087089 m