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Which of the reagents listed below would efficiently accomplish the transformation of CH,CH,CH=CHCH,CH,CHO into CHỊCH,CH,CH,C
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Answer #1

Converting aldehydes to primary alcohols is Reduction process.

-CHO is changes to -CH2OH group.  

Out of the given reagents KMnO4 is oxidising agent.

Br2/CCl4 is also oxidising agen (by brominatinng unsaturation)

H2/ Ni is a strong reducing agent which reduces aldehydes to promary alcohols , ketones to secondary alcohols and unsaturation compound to saturation comppunds.

NaBH_{4} ( Sodium Borohydride) is also reducing agent but it cannot reduce unsatiration .

Sodium borohydride is mild reducing agent and it is not strong like LiAlH4 ( Lithium aluminuum Hydride.)

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So of the given the are two options H2/Ni and NaBH4

But H2/Ni is capable enough to reduce completely given 3-Heptanal to n-Heptanol

So best choice is H2/Ni

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Which of the reagents listed below would efficiently accomplish the transformation of CH,CH,CH=CHCH,CH,CHO into CHỊCH,CH,CH,CH,CH,CH,OH? 4...
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