Question

You have prepared a solution by dissolving 14.659g of dodecane (C₁₂H₂₆) in 40.00mL of cyclohexane (C₆H₁₂) at 25°C. What is the expected vapor pressure (in units of mmHg) of this solution? At 25°C, the density of cyclohexane is 0.7792^g/_mLand its vapor pressure is 97.5mmHg. Assume that dodecane is a non-volatile solute.

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mole of dodecane = 14-659 gm 170gm/mol 0.086 mol 0.7792gm x 40ml = 31-17 gm mass of cycloberane = dXV = mole of 31-17gm Cyclohexane mi 0.37 mets sugr/mol 25 total mol= 0.0864 0.37 = 0.456 mole 0.37 mole fraction of cyclohexane = mole of cyclohexane total mole 0.456 Psolution Pyelohexane xx cyclohexane 97.5mmity X 0:31 0.45€ 30 -179.11mm mmHg