Find the complex numbers corresponding to 21 = Scis3 and 22 6cis?

Question

Question

Answer 1

Answer #1

Solution z = 8 ci8 37 2 = 8 (Cox 3T + i sin af - © COPI 4-6-87 lor 12 6 cis 77 3 6 Cos II tisin 70 3 19 + 3 13 2 61 2 & +16 7

Answer 2

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