Question

Ex 1 A ball is thrown upwards with the velocity and the angles shown in the drawing. 20 m/s 10 m/s 37" 53 10 m/s 45 10 m/s 30° Order from greater to smaller 1. The vertical component of the velocity 2. The horizontal component of the velocity 3. What is the speed of the ball when reaching the highest point of its trajectory.

Answer 1

1) v1 = 10*sin(37) = 6.01

v2 = 20*sin(53) = 15.97

v3 = 10*sin(45) = 7.07

v4 = 10*sin(30) = 5

Order : v2>v3>v1>v4

2) v1 = 10*cos(37) = 7.98

v2 = 20*cos(53) = 12.03

v3 = 10*cos(45) = 7.07

v4 = 10*cos(30) = 8.66

Order : v2>v4>v1>v3

3) at the highest point of the trajectory the velocity of the projectile is always zero.