Question

1 (50%). Water enters a cylindrical pipe (inner diameter = 1 inch) with a metallic wall (thickness = 1/16 inch, km = 152 W/mK) at a volumetric flow rate of 1 liter per minute, and the inlet temperature, Tm,i= 150 °F. There is an external cross flow, as shown in the sketch with air speed of 1 m/s and ambient temperature of 32 °F. (a) What are the pipe dimensions and temperatures in SI units? (b) What is the length of the pipe for which the exit temperature falls to 0.5Tmi? (c) In order to answer (b), you would have assumed const q3" or Ts. Ts is the temperature at the inner pipe surface. Compute q;" or Ts at the inlet and the exit, and justify the assumption. If needed, go back to (b) and re-calculate with the more justifiable wall boundary condition.

help the following problem and show work, thank you.

Answer 1

do = solution inner diameter dia linch outer " ditat = 1+2x I 16 do = 1.12 sin do inlet Temperate Tmi = 150°F Te = 0.5 Tmi =75F surface Temp Ts = 32°F out but SI mit di= 0.025 um do = 0.028575m. Tmi - 65.55°C 23.88°C = 338.7055k - 297.0388 K Te 새 = 0°c = 273. 18k. it J J I Is = constant Idi O= 1x10 m/60s = lot m/s O=A v

But consider Fully develd plow My = 3.66 1x104 II X (0.025) 3 v 6 4 v=0.03395 m/s 2 2 film Temperatue Tf = Tit Te = 65.55 +23.88 1Tg = usc take properties of water at usč S = 9go. 1 Kg/m3 M = 0.5968103 kg /m.s K = 0.637 W/mK. Pr = 3.9) = Re SVD 990.1 X 0.03395X0.025 0.5966103 Re=1409.97 Re< 2300 (laminas flow) Ditus bolts Equation For lamines flow. Nus 0.664 Re oorp 0.33 - For constent Temperature. My hdi ਕਰ ਰਹੇ ਸਨ।

3.66X0.637 -hi 0.025 hi = 9 3.25 w/m²K M = SAV = 80 = 990.1X10 4 mag's m = 0.01650 kg/s. 6 As ODL h As Te = Ts-(Ts - Ti) e milo -HAS (TS-Ti) e inice (23.88-0) 93.25X AS 23.88 e 4180x0 .01650 (0-6.55) 1.3520 As (0.3643) ln (0.3643) = -lne (1.3520 As) As = 0.7468 m2 - IT DiL L = 9.5095 m. Kindly vole up.

mcp o Tom = n (Ts-Tm) dets TS increase the energy of fluid el As pda Te = Ti d (Ts - Tm ) dindo - hp da in cp Ts- Tm at a=0 x=L inlet Tm=Ti outlet Tm = Te X=L - hp da imco Te = d (Is-Tm ) (Ts - Tm) x=0 T - en TS-Te TS- Ti has mep has = e mice Ts - Te Ts-Ti vote Kindly up