Question

Example 4 A beam of wide-flange shape is subjected to a vertical shear force V=45 KN. The cross-sectional dimensions of the beam are b=165 mm, t=7.5 mm, h=320 mm, and h =290 mm. Determine the maximum shear stress, minimum shear stress, and total shear force in the web. 330 mm 17.4 MPa 200 mm 1 = 75 mm 210 MP 165 mm b)

How do you find the total shear force in the web? Would appreciate if the solution would be shown in steps. Thanks!

Answer 1

15mm I Tmin= 17.4 MPa 290mm Tmax 21 MPa 1 45min tren - Isma II 17. UMPa. * 165mm from bottom 9,- 15-7.5 Yo =15+290 - 160 mm from bottom * = 15+290 +1$ = 319.5 m from bottom Tý= A, Y, + A2 Y₂ + Az Y3 A, + Azt Az (15x165x7.5) + (290x7.5x160) + (15X165*319.5) (15X165 +290 *7.5 * 15x165) u 1140000 7125 160 mm TO Calculate total theal force in the web = (Area Thear stress Cusue of web) of x width of wel

VEO Trapezoial formula f(n)= 17.4 MPa halus mmg f(n) = 21 MPa n=ggo mm f(n)= 17.4 MPa h= Interval= 290 = 145mm Area of where whes Cunnes heffers) + f(1990) +2 f(mus)] 145 (17-4 +17.4 +2(21)] 2 - Ss68 N xmm. mm² - total sheas face in web 5568 x 7.5 (width) 41.76 KN As we known that Most of thear is taken by web.