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4. A ray of light in water is travelling parallel to the base of a glass tank. The tank has a 50° angle with the horizon. The
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Z P { 500 . 50 by drawing the normal line ON we get at point o, the angle of incidence is 90-50°- 40°bays that so, the pays that would be partially reflected, have angle of reflection Reflections a with the Normal ce ON so ang- 8 = 34.74592663 p = 34.75 appoon) Now, if we draw perpendicular ( normal live mp) at the grass-win interface at point in,we get, i= sinthiis sin (34.7459266 y ✓ = 58.74951959° Cappoon) 58.75° 2 the TA we know that if e is speed of light in emptyso, travel the fastest The light through ain &, The light travel the slowest through the glass .

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