Question

2) A ball is dropped from rest at a height H. At height h (below H) the ball bounces off a surface with no loss in speed. The surface is tilted at 45°, so the ball bounces off horizon- tally. Derive an expression for the distance the ball travels in the horizontal direction. Plot the distance traveled in the horizontal direction as a function of h where h varies between 0 and H.

Answer 1

Do not put the value of h as 0 and H directly in the formula, this may give wrong result for the plot because we are actually multiplying time which is always increasing. So at h=0 distance covered cannot be zero but maximum. So while plotting keep this in mind. If you think my answer satisfies you give me a thumb up.

H ch lehere The ball is dropped from rest. Eve know, u2 t das &= final speed u = initial speed a = acceleration = + g = 9.8 ms s = distance movelled - H-h velocity at the point of bouncing aff=√ 2x g *(4-4) '; the surface of which die ball bounces is filed at 45° i. the ball leaves the :. Distance covered by the ball Voxt V2g (+ - h) casot V2 g (H-ht t is the time taken by the ball to reach the ground surface. homizontally 2h .. Distance covered by the ball = 2 g (H-h) Josh Distance travelled = 25h (H-h) H height -