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Reserve Problems Chapter 11 Section 2 Problem 1 The department of health studied the number of patients who need liver transp

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Answer #1

x

y

X-X

y-ý

(y-7) (x - 1)

(x - 2)2

(y – 5)2

2004

1327

-6

-4772.69

28636.15

36

22778592

2005

1898

-5

-4201.69

21008.46

25

17654218

2006

2865

-4

-3234.69

12938.77

16

10463234

2007

3870

-3

-2229.69

6689.077

9

4971528

2008

4867

-2

-1232.69

2465.385

4

1519530

2009

6806

-1

706.3077

-706.308

1

498870.6

2010

7576

0

1476.308

0

0

2179484

2011

7495

1

1395.308

1395.308

1

1946884

2012

7772

2

1672.308

3344.615

4

2796613

2013

8553

3

2453.308

7359.923

9

6018719

2014

8495

4

2395.308

9581.231

16

5737499

2015

8704

5

2604.308

13021.54

25

6782419

2016

9068

6

2968.308

17809.85

36

8810851

Total

26130

79296

0

0

123544

182

92158441

Mean

2010

6099.692

The regression equation between two variables can be given by following equation

ỹ = 60 + b1 * *

The estimate of b0 and b1 can be obtained by least square method.

The least square estimate of b1 can be given by following expression

b1 : Σy - y) * (x – x) Σ(x – x)2

bl: 123544 182

b1 = 679

The estimate of b0 can be given by

b0 = 7 – b1*

b0 = 6099.692-(678.81) * 2010

b0 = -1358315

The final estimated equation of line can be given as

ŷ = -1358315 + 679* x

The ANOVA table of fitted regression is given by

Source

Df

SS

MS

F

p-value

Regression

1

b1*Sxy=679*123544

         = 83863296

83863296

111.21

4.34E-07

Error

11

8295144

754104

Total

n-1=13-1=12

SYY=92158441

Now we can answer the given questions

Answer(a):

Here we have, MSE =754104 which is estimate of σ2

o2 = 754104

Answer(b):

B1 = 679

Answer(c):

The estimate of patients in 2018 can be obtained as below:

û = -1358315 + 679* 2018

y = 11530

Answer(d):

The fitted value of y for x=2014 is

û = -1358315 + 679* 2014

y = 8815

The residual can be obtained as below:

e = y-

8495 - 8815

e = 320

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