If 2.0 moles of LiOH are neutralized by 1.0 mole of an acid in aqueous solution, then
A. |
the acid is twice as concentrated as the lithium hydroxide solution. |
|
B. |
the lithium hydroxide solution is twice as concentrated as the acid. |
|
C. |
2.0 moles of acid supply one mole of hydrogen ions. |
|
D. |
1.0 mole of acid supplies 2.0 moles of hydrogen ions. |
|
E. |
1.0 mole of acid supplies 1.0 mole of hydrogen ions. |
It is acid base neutralization Reaction.
M*V = mole= n
nf = n-factor: number of H+ or OH- given by any acid or base.
nf= 2, means acid will give 2 moles of H+ for neutralization
Reaction.
If 2.0 moles of LiOH are neutralized by 1.0 mole of an acid in aqueous solution,...
18. (5 pts.) A 155.0 mL portion of aqueous phosphoric acid solution was completely neutralized by 45.38 grams of Lithium hydroxide. The chemical equation is: 3 LiOH (s) + H2PO4 (aq) → Li3PO4() + 3 H20 (1) The concentration of the phosphoric acid, in molarity, is: (a) 4.075 M (b) 1.611 M (C) 11.40 M (d) 3.942 M
18. (5 pts.) A 155.0 mL portion of aqueous phosphoric acid solution was completely neutralized by 45.38 grams of Lithium hydroxide. The chemical equation is: 3 LiOH (s) + H3PO4 (aq) → Li3PO4 (s) + 3 H2O (1) The concentration of the phosphoric acid, in molarity, is: (a) 4.075 M (b) 1.611 M (c) 11.40 M (d) 3.942 M
18. (5 pts.) A 155.0 mL portion of aqueous phosphoric acid solution was completely neutralized by 45.38 grams of Lithium hydroxide. The chemical equation is: 3 LiOH (s) +H,PO, (aq) a Li,PO, (s) + 3 H20 (1) The concentration of the phosphoric acid, in molarity, is: (a) 4.075 M (b) 1.611 M (c) 11.40 M (d) 3.942 M
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moles of h3o neutralized with oh and heat of neutralization
per mole of h3o neutralized
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