Question

Question 22 1 pts Determine the molar solubility of BaF2 in 0.049 M Naf. It's Kop is 1.5 x 10-6 Our system can't handle your tiny answer, so multiply it by 1000 before entering. Question 23 1 pts Select any of the given acids, when in solution with an equal number of moles of its conjugate base, that would have a pH very near 8.64. HNO2 HC2H502 HCN OHBro HF HCIO HCOOH HCIO,

Answer 1

Ane BaF2 (8) Beltrapp +2f1agy V Initial 0.049 M Equilibrium SM Lo.oug +28) M conco Here, s is solubility of Bata in water. Ksp = [Ba2+] . LF-1? 1.56 10-6- s. l6.049 +28) ² Now, s is very small worto 0.049, o.aug+25 o.aug. See 6 cseanned with Camscanner = S X 10.0492 desxlo

s= 6.2474xlo-4M 1.5x la- (0.0492 se, multiplying (to ܘܘܘܐ ܨܟ give answer in the both Answer - 0.62474 o When moles of acid and its conjugate are equals base pH of an acidil given asi IPH= pka logo [Conjugate based [Acid] becomes HNO2 pka = 3.15 b HC₂H30₂ pka = 4.76. HCN -> pke= 9.2 → HBrO → pka= 8.55 -HF → pka = 3.1 - Helopka = 7.54 -HCOOH + pkez 3.75 HC102pkez tel so, and wer can be given HCN, HBrO, HClO and Hela CSScanned with CamScanner