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3. Presently, the mean life expectancy of a rare strain of bacteria is 12 hours. A scientist claims that she has developed a
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Answer #1

Given that the mean life expectacny of a rare strain of bacteria is 12 hours

The scientist tests 25 cultures and find that they have a mean life of 13.25 hours with a sample standard deviation of 2 hours

So Sample mean r = 13.25 hours

Sample Standard Deviation S = 2 hours

Sample size n = 25

The scientist claims that the mean life expectany is not 12 hours

Question (a)

Null Hypothesis H0 : 1596104181659_blob.png = 12

Alternate Hypothesis H0 : 1596104181622_blob.png 1596104181628_blob.png 12

The Null Hypothesised value is 1596104181614_blob.png 0 = 12

Question (b)

Given that the mean life expectacny of a rare strain of bacteria is 12 hours

The scientist tests 25 cultures and find that they have a mean life of 13.25 hours with a sample standard deviation of 2 hours

So Sample mean r = 13.25 hours

Sample Standard Deviation S = 2 hours

Sample size n = 25

Here we use one sample t-test since n is less than 30 and distribution is assumed to be normal

t-test statistic = (1596104181696_blob.png - 1596104181561_blob.png 0) / (S / 1596104181735_blob.png )

= (13.25 - 12) / (2 / \sqrt{25} )

= 1.25 / (2 / 5)

= 1.25 / 0.4

= 3.125

Given significance level = 0.05

Number of degrees of freedom = n - 1

= 24

The critical t-value for 24 degrees of freedom at 0.05 significance level for a two-tailed test = 1.711

The p-value for a t-score of 3.125 and 24 degrees of freedom for a two-tailed test = 0.00460264 from online calculator

Question (d)

Since the test statistic of 3.125 is greater than the critical t-value of 1.711, we reject the Null Hypothesis H0 and conclude that there is enough evidence at 0.05 significance level to support the scientist's claim that the mean life expectany is not 12 hours

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