In a 1.5 liter flask in which the vacuum has been made, 0.08
moles of N2O4 are introduced and heated to 35 ° C. Part of N2O4
dissociates into NO2 according to the chemical balance:
N2O4 (g) ↔ 2NO2 (g)
When equilibrium is reached, the total pressure is 2.27 atm.
Calculate the partial pressure of NO2 at equilibrium
In a 1.5 liter flask in which the vacuum has been made, 0.08 moles of N2O4...
A flask is charged with 1.800 atm of N2O4(g) and 1.00 atm of NO2(g) at 25 ∘C , and the following equilibrium is achieved: N2O4(g)⇌2NO2(g) After equilibrium is reached, the partial pressure of NO2 is 0.519 atm . 1A) What is the partial pressure of N2O4 at equilibrium? 1B) Calculate the value of Kp for the reaction. 1C) Calculate the value of Kc for the reaction.
A flask is charged with 1.500 atm of N2O4(g) and 1.00 atm of NO2(g) at 25 ∘C , and the following equilibrium is achieved: N2O4(g)⇌2NO2(g) After equilibrium is reached, the partial pressure of NO2 is 0.519 atm . Calculate the value of Kc for the reaction.
A flask is charged with 1.500atm of N2O4(g) and 1.00 atm NO2(g) at 25 degree C, and the following equilibrium is achieved: N2O4(g) 2NO2 After equilibrium is reached, the partial pressure of NO2 is 0.519atm. Calculate the value of Kp for the reaction. Calculate Kc for the reaction.
A flask is charged with 1.500 atm of N2O4(g) and 0.94 atm NO2(g) at 25°C. The equilibrium reaction is given in the equation below. N2O4(g) 2NO2(g) After equilibrium is reached, the partial pressure of NO2 is 0.512 atm. (a) What is the equilibrium partial pressure of N2O4? ______ atm (b) Calculate the value of Kp for the reaction. ______ (c) Is there sufficient information to calculate Kcfor the reaction? -Yes, because the temperature is specified. -No, because the value of...
At a particular temperatur KP=0.70, for the reaction N2O4<->2NO2 a A flask containing only N2O4 at an initial pressure of 3.7 atm is allowed to reach equilibrium. Calculate the equilibrium partial pressures of the gases. PARTIAL PRESSURE OF NO2 N2O4
4) A 1.000 L flask is charged with 0.375 moles of gaseous N2O4 which is in equilibrium with gaseous NO2 with ΔH = 58.02 kJ/mol and ΔS = 176.6 J/(mol*K). What is the pressure in the flask at 300. K? (15 pts) (Hint – Solve for G, solve for K, solve equil. concentrations, and then how many moles of gas are there?)
At a particular temperature, Kp-0.39 for the reaction below. N204(g) 2 NO2(g) (a) A flask containing only N204 at an initial pressure of 4.8 atm is allowed to reach equilibrium. Calculate the equilibrium partial pressures of the gases. N2O4 NO2 atm (b) A flask containing only NO2 at an initial pressure of 9.6 atm is allowed to reach equilibrium. Calculate the equilibrium partial pressures of the gases. No2 (e) From your answers to parts (e) and (b), does it matter...
please show all work thanks B. Consider the system N2 (9) 3H2 (g) 2 NHs (9) dbie of NHs was placed in a 2.000 liter flask at 25°C. When equilibrium at that temperature, it was determined that the ammonia was reduced A 2.568-g sample was reached N to 75.0% of its original value. 1. Calculate K for the decomposition of 2.00 moles of ammonia at 25.0°C. 2. Calculate K for the decomposition of 2.00 moles of ammonia at NH3 is...
1. For the following balance: 2 HF (g) H2 (g) + F2 (g) 73Kcal Indicate what will happen with each of the following changes: a) Decrease in HF concentratiorn b) Increase in temperature c) Decrease in pressure d) Increase in H2 concentration ej Increase in the concentration of F2 2. At 130 oc the sodium bicarbonate, NaHCO3, decomposes partially according to the following equilibrium: 2 NaHCO3 (s) sNa2CO3 (s) + CO2 (g)+ H20 (g) Ko= 6.25. 100 g of NaHCO3...
1. Procedure A. Lithium 2,6-dimethylphenoxide. In a 300-ml. flask, equipped with a magnetic stirrer and a reflux condenser and flushed with nitrogen, are placed 150 ml. of toluene (freshly distilled from sodium), 1.40 g. (0.202 mole) of lithium metal (Note 1) and 25.0 g. (0.205 mole) of resublimed 2,6-dimethylphenol. The mixture is heated under reflux with stirring for 36 hours; a nitrogen atmosphere is maintained for the reflux period (Note 2). The condenser is replaced by a distillation head with...