Question

A2-minute totally containing strated water vapor Mais comece to supply line that carries steam at 200C. Now the speed and 18. Ale temperature is more to be 300 c O 477 O The mass of wide 1322 23220 12 O 24310 542 The theorets

Answer 1

Answers:

(0) Given data Volume of the tank (V) =am Initial pressure in the tank (P.) = 1.3 MPa Final Pressure in the tank (P2) = 1.8 MPa Final temperature of steam in the tank (1x) = 300C Temperature of steam in the line (TZ) = 1200°C = 1300 kPa supply line steam, T = 12.00°C From steam tables (saturated waten-Pressure) at P, = 1.3MPa Specific volume (vi) = Vy = 0.15119 m²/kg Internal energy (u) = Ug = 2589.9 kJ/kg V=2m3 insulated (sat. water vapour) Tank P,= 1.3MPa From steam tables (super heated waten) at P₂ = 1.8 MPa = 180okPa fig. 1 (initial) supply line T₂ =300°c. steam, T = 1200€ specific volume (V) = 0.14025 m²/kg Intemol energy (u) = 2777.4 KJ /kg, l insulated v=zm3 P2 = 1-8MPa Tz = 300c Tank fig. 2 (Final) The initial internal energy in side tank (u) u, - 2589.9 – 2591 kJ/kg 4, = 2591 KI/kg The final internal energy inside tank (42) U₂ = 27774kJ/kg The initial mass of water inside tank (m) m, = V Vi 0.15119 2 m, = 13.22k9 The final mass of water inside tank (m₂) V 2 0:14025 m₂ = √3 = 294025 m₂ = 14.26kg The enthalpy of steam that has entered to tank (h.) h = m2 4₂-m, u 14.26(2777-4) -13.22 (2591) m₂-m, 14.26-13.22 h, -5146.83 kJ/kg

1. u1 = 2591kJ/kg

2. u2 = 2777.4 kJ/kg

3. m1 = 13.22 kg

4. m2 = 14.26 kg

5. h, = 5146.83 kJ/kg.