How many grams of CuCl2 are required to prepare 1250 G of a 1.255% CuCl2 solution,
Given,
mass percentage = 1.255%
mass of solution = 1250gm
subsituting these values in the above equation,
15.6875gm is the amount of CuCL2 needed to prepare a 1.255% of 1250gm of solution.
lets see how thus make sense ,if we have a 1250gm of solution then a 10% of somwthing would amount for 125gm in thaat solution and similarly a 1% will amount for 12.5 gm in that solution . as we have to make a 1.255% our answer came out to be near to 1% that is 15.6875gm
How many grams of CuCl2 are required to prepare 1250 G of a 1.255% CuCl2 solution,
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