8]
Flux= Magnetic field*Area
Flux= 20[(0.25)2]= 3.927 3.93 Wb
9]
e=Induced emf= Rate of change in flux
N=Number of turns
A=Area
B1=Magnetic field intially
B2=Magnetic field finally
t=Time interval
e= -NA(B2-B1)/t= -1*(0.25)2*(4.8-1.5)/0.023= 28.17 V
10]
e= -NA(B2-B1)/t= 50*(0.2*0.2)(5-3)/0.1= 40V
I=Current= e/Resistance= 40/20= 20A
11]
e= -NA(B2-B1)/t= 100*0.25*(2*1.5*10-4)/10*10-3= 0.75 V
12]
Induced emf in moving rod= BVL
B=Magnetic field
V=Velocity of rod
L=Length of rod
e=BVL= 8*2*0.45= 7.2 V
In the above answers, we had calculated only the magnitude of induced emf
please help... Thanks in advance I appreciate your help 8 A magnetic field of 2.0 T...
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