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3) For which of the folling pure chemical substances will Sº = 0.0 J/mol-K when T = 25.0 °C? a) O2(g) b) O3(g) c) FeCl3(s) d)
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Answer #1

According to the third law of thermodynamics the standard entropy of a perfectly crystalline substance is zero at absolute zero temperature. that is the standard change in entropy of a substance will be zero if the temperature is zero kelvin.

Here as the temperature given is 25 degree Celsius which is equal to 298 Kelvin. So none of them will have S° as J/molK.

So the correct option is- e) none of the above

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