So as two dolphins move toward each other that's why resulting frequancy heard by receiver attached to dolphin B increases due to doppler effect
and given by
here f= 1222Hz
v= 5518.8 km/h = 1533m/s
and vr = 7.31 m/s
vs = 4.87 m/s
so we get
f' = 1231.74 Hz
2) Speed camera measures speed of vehicle using doppler effect so sound waves must be used here
true
3) So,
q= 13.86 cm
f= 20.46cm
so,
so
so we get object distance from spherical mirror
p = 42.97 cm
A dolphin (Dolphin A) is swimming under the ocean at a speed of 4.87 m/s, emitting...
Question: A diver underwater sees a dolphin swimming towards him with a speed of 7.257 m/s. The diver gets excited and swims towards the dolphin with a speed of 11.994 m/s. The dolphin sees the diver and emits a call with a frequency of 22.73 kHz. Assume that the speed of sound through the water is 1521 m/s. Part 1) What frequency does the diver detect coming from the dolphin? f= kHz Part 2) The sound is reflected off the...