Question

I need a solution to the maximum within an hour in the subject of electricity technology

*.Q2/// Find Thevenin's equivalent across the 2 Ohm resistor for the circuit below 4v 20 129 12 lov 2v 842 22 -6v 8V 332 232

Answer 1

Solution uu 20 ou unit 422 ܘܐ 2.1 A B the mums 2V OV 8v 32 Зл we require across an To calculate Theven in equivalent Thevenin resistance terminal and Rth bro A & B terminal open circuit Thevenin- voltage (th) of A-B Thevenin equivalent we'll be ata A Uth B Thevenin resistance (Rth) Roth calculate blw A&B To deactivate all voltage 1 sources and replace them by Short-circuit 1 Rih is net resistance of circuit.

in un A Rth B 34 32 Due IN 11 30 to short circuit of battery Tov and yell 3R 3. Ҷл ३२ f A 11 Rth Rth [(311) + (413)] 1 3X1 43 ( ch + ) 3+1 4+3 Rth a 12. 2 12 Rth 2.464 a so this is the net Rth across Qot resistor.

Thevenin voltage ( vta) To 2 resistor and Uth calculate will remove we terminal voltage of then calowate open- eircuit A - B terminals. d 1 uv 14 un 12 2v + e lov J th A th B 8V 6V 32 31 f H is so circuit corrent no branch Middle , will open. that flow from > let current I flow în î primary branch (C-J-6) Secondary branch (d-e-f) and Current Iz flow lor ) » Apply kr în poſmary - loop (including 10 of 4 + 1(1,) ~ 6 + 3(71) = 41, -12 2 I, a 12 A 3 A 1

Apply kve i secondary loop including (hov) (1-c-d-e-fa 6 - H-I) loop lo 2 + 4(12) + 8 +3 (2) - ru +7 I Iz = 4 7 I2 0.5714 A find With So we con we Now have In & Iz by using kr kr equation în loop CA -J-e-de -A P Vth -2 -1(11) -4- 2 + 4( 12) - Veh -8-|(3) + 400-5714) - Nth 11 - 2- 2857 Vth 8.7142 v Qgoss if we take it took Nth across A-B B-A terminal then Vth a 8.7142 v ** INth Magnitude of 8-7142 V series be Thevenin will equivalent Combination of th & Rth with 2h resistor.

Thevenin equivalent Rth mm 2464 1 Ansi Uth 8.7142 V 22 The sum of all voltage KUL > According to is always bero. a drop in closed loop volt. doop is the in the direction of current