Question

+ X cm XA 4- Determine member force GC and GF. B D И 2 m A 250N 2 m 2 m 2 m Ee....jpg 35fdc7e6-a20f-4c9....jpg

Answer 1

2m solution: Im Bike 2m 2ń А. G E 250 Assuming all members are in teaslon(tve) Joint sign convention :- Tension compression Take Joint A All angles are 45 By method of Joints EV=0 vertical conces FAB Foo Sin 45 250 = 0 AB E 250 AS FAB 250 (Y) E AB 2 +250 12

Horizontal Houses EH=0 Cos 45 + FAG 'AB AG FAGE - FARI - - 250.64 mily FAG -250 (comp) Now Take joint B {H=0 Hbwizontal forces FBC - - F*CQr45 =0 AB BC 459 FAR SC FBC = + FR Cos 45 = 250 V2 *1 ra F C = 250 (Tension) Now By method of sections in Cut the thuss through members BC, GC, GF FBC For this section, B Facy Ev=o $6, For Sin 45° - 250=0 a A GF 250 - 250 Fac () Face = 250 12 / (Tension)

Now, EH=0 Fact TE + Fac 60545°-d GF 250+ For + 250 W* E ar = - 500 (Comp)