Question

Combined loading A rod with the diameter of 20 mm is subjected to a force P - 1800 N, as shown in the figure. The rod is fixed to the wall at Point C.L.- 50 mm and L-200 mm. Determine the magnitude of the shear stress MPa at Point Blocated on the surface of the rod on the designated positive z axis (rounding to two decimal places).

Answer 1

Given dato's u = 50 mm dz 20 mm p = 180oN Logite Laz 200 mm draw the free body diagram at section shown figure. AA in y A v=8 = 1800N Z G A T = PALI M2 =PXL2 where moment M₂ = PALL M2 = 1800 X 200 - 0.368106 pmm torque Ta pal T- IGOOX 502 9000 ) Oo C mm. Shear fore v=P - 1800 p

Cross find h of rod. sectional properties Area Az TV बर Max 902 = 319. 16 mm moment al inertia Iz = ly T d 64 In - Iya T x 204 7854 7859 mm2 polor moment of inertia J = T 12 da x 2042 4 15708 mm 12 find ho torsional Stress at point Tr Tx() 90000 x Its J 15708 en 57.295 mpa

find the moment of area of of thatched cross section shown in the as figur below. rat 20 =lomm 2 ATE() (* qr 1 T - ar Ý - ax fo 30 Ay = 1 BT 2 IT 2 bid= 20mm Ay=666.67 mm find the shoor slegs at point A due to frans verse عيووو -- VAY lgoot 666.67 Izb 70 54 x 20 x = 7.64 MPa find the to tal Shear stress of point R. TB z e't 7.64 t 57.295 TB - 69.915 Mpa