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5. For this series of 4 questions, a rider rides in a car that is connected to a 4-m rod, and rotates about the z axis. The r

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Answer #1

We have,
Radius \rightarrow R=4\ m
Constant couple moment \rightarrow M=740\ Nm
Traction force → F= 100 N
Initial time \rightarrow t_{1}=0\ s
Final time \rightarrow t_{2}=6.7\ s

The angular impulse H is given as:

H=\sum \int_{t_{1}}^{t_{2}}M\ dt

\therefore H= \int_{t_{1}}^{t_{2}}M\ dt+\int_{t_{1}}^{t_{2}}FR\ dt

\therefore H=M+R\int_{t_{1}}^{t_{2}}10t\ dt

\therefore H=M+10R\int_{0}^{6.7}t\ dt

\therefore H=M+10R \left (\left (\frac{t^{2}}{2} \right ) ^{6.7}_{0} \right )

\therefore H=M+10R\ ((6.7^{2}/{2} )-(0^{2}/{2} ) )

\therefore H=740+(10\times4\times (22.445))

{\color{Blue} \therefore H=1637.8\ kg\ m^{2}\ s^{-1}}

Therefore, the magnitude of angular impulse on the raider from the angular momentum is {\color{Blue} H=1637.8\ kg\ m^{2}\ s^{-1}} .

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