Question

A random sample of n = 137 individuals results in X1 = 45 successes. An independent sample of n2 = 151 individuals results in X2 = 58 successes. Does this represent sufficient evidence to conclude that p; <P2 at the x = 0.01 level of significance? Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). Click here to view the table of critical t-values. Click here to view the chi-square critical values table. The given situation is about a Write the hypotheses for the te proportion, p. Ho Hii mean, u. Scale document down standard deviation, o, or variance 62 Calculate the test statistic. (Round to two decimal places as needed.) Identify the critical region. Select the correct choice below and fill in all answer boxes within your choice. (Type an integer or decimal rounded to two decimal places as needed.) O A. test statistic or test statistic > OB. test statistic O c. test statistic > What is the conclusion? the null hypothesis and conclude there sufficient evidence that the parameter of interest of population 1 is the parameter of interest of population 2 at the a = 0.01 level of significance.

Answer 1

Answer:

Given,

sample proportion p1^ = x1/n1 = 45/137 = 0.3285

p2^ = 58/151 = 0.3841

p = (x1+x2)/(n1+n2) = (45+58)/(137+151) = 0.3576

Ho : p1-p2 = 0

Ha : pi1-p2 < 0

test statistic z = (p1-p2)/sqrt(pq(1/n1+1/n2))

substitute values

= (0.3285 - 0.3841)/sqrt(0.3576(1-0.3576)(1/137 + 1/151))

= - 0.98

P value = 0.1635431 [since from z table]

= 0.1635

Here p value > alpha, so we fail to reject Ho.

So there is no sufficient evidence to support the claim.

Post the remaining question as separate post. Thank you.