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Consider the following computer output for an experiment. SS Source DF Factor 5 MS F P-value ? ? ? Error ? 27.58 ? 29 66.14 T

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Source DF SS MS F P-value n factor Emor Total 5 & 8 27.58 66.14 3 8 29 a) There 6 replicacbee Degrees of freedom DF factor =IMS (Fachos) = 12 fe Ms (factor) MS (Emor) 7,712 1. 149 F= 6.711 p-value = PCF> 6.771) = 0.00048 - P-value = 0.00048 T2 SS(To

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