Homework Answers
Answer:
As we have five carbon alkyl halide which needs to be converted to six carbon alkyl amine.
So we need to react with NaCN to produce the cynide group.
Followed by reducing the cynide with LiAlH4 to have six carbon amine
CH3-(CH2)4-Br + NaCN --->CH3-(CH2)4-CN ------------> react with LIAlH4 + H2O -------> CH3-(CH2)5-NH2
The reaction shows as below:
CH3-(CH2)4-Br + NaCN --->CH3-(CH2)4-CN (Nucleophilic substitution)
Now further reaction shows in the belwo image
So correct answer is :
Reagent 1: NaCN
Reagent 2: LiAlH4
Reagent 3: H2O
Add Answer to:
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