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A coaxial cable, as shown in Figure 2, consists of an inner conductor of radius a, surrounded by an outer conductor of radius
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Q:sotni a co-axial Cable: Iriner radins a onter-radius=b length =l lo &ļa Electric field equation, Inside The Cable. É (8)= av= ah, dran e put value of Efr) from ean attre b. (radran=1) dy 2 Tel ln (bla) (Ins) a b 2TTEI ZTENon, VE In (bla) If=fo fr 2 T Go frl proved C) soln capacitance per unit length V 11 с ula Vol In (bla).l 2 T to fr v from eanGo= 885*10/2 Flm, Graf (ais) ar=1.681519c, la lome given @=5mm, b=10 mm ( ginen hence, V = 1.6 15 9 Anl ul 2x374x885*102x10 vCapacitance : ca 2T to Gr il ( from eve) In( blas c=2*3.148 8185x152, xlo In (1015) = 801&2 X1012F C= prol8x1öloF hence Energ

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