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Assignment 4 Water (y=9.81 kN/m", vapor pressure = 4.215 kPa (abs)) flows in a series pipeline system from a lower reservoir to an upper closed tank as shown in Figure below. The system require to deliver of 55 litres/s of water. Assume atmospheric pressure Patm = 101.3 kPa. Closed tank Ko Pressure 30kPa (abs) Ks 33 m R2 Pump K3 Suction pipe 22 200 0.0112 Length (m) K4 Diameter (mm) Friction factor Discharge pipe 50 150 0.0109 ка х Kj K KE Ks Loss coefficient 0.3 08 08 0.3 0.3 0.8 Figure 1 Design a pump to meet the design requirement. Specify the impeller diameter, efficiency, and power output of the pump. Determine the maximum elevation X of the pump placement to prevent cavitation Submit your scanned solution file (in pdf) to google form:

Answer 1

Yz4g=9.61 KM Pa oor m² o lot Petm=1013 kPa Sec sec - 15omm. Pr Pabs Prap = 4.215kpa, ds-200mm, dal (abs) Kg 30 K2 2 K3 Ki 33m .P ky ds 1 Pa is 22m From ld fa0.0109 K-0-3, ky 20.8=k=k K2 - B: ks = k, =0.3. so kisend 0.3, Kralke oog fs ED.0112 vs 0.005 S As al 75m/sec My(0.232 Oos 1 ola 2 va - 3.112 m/see Aly (o.rs)? Applying Bernoullis teorem. equation, between (1) & (2). and P₂ € Pr 4.215 kPa - Psiction Pi eg + V? zg T + P2 47 ga= zg + gazt his املاح 4,50 ,2,50, (datum), PicPAm = 1011 3 kPa V = Vs = 2.75 m/sec, 22 = x,

hesa hand th 'farction that 'Valve his koki ve zg + fs R v2 + K₂ vs ag ds zg his = 0.3x 1.252 0.0112 x 22x1.75? + 2x9.81 toisx 1.72 289-81 8 0.2 249.81 hesa 0.364 m from equestin (2) 101.3 (kPa) 4.215 1.752 | Otos f 9.81 kPa 9.85 + x +0.364 249181 10:3262 - 0.95 79.3762 m. X 9.3762m By Bernoullis Equation between section @ and (. How we are looking at discharge line , P, Pd, v=0 2=X Va 2 P₃ + 2 x eg Zz,the Pa f Pg + ot Pd P₃ eg d ² + (237) that eg zg

hed 11 2 x hond t 2 hvalret 2 hrane + had va? - 2x 2 xk Kend + 2x Kralne va? zg + zg fald V ? zg dd 0.34 3.11 22 3.1122 0.0109x30x3.112? t O. 88 + 249.81 9.81 2x9.8180.15 1.086 t 1.8 had = 2.88m Now, from equation (2). 30 3-1122 + 33 9.376) + 288 ha 1) Pa eg 2x9.81 9.81 Pd E 285.162 kPa hd = 29.0685m

- Total head inlet) thaoss. Hranare free = Hm = (Total head outlet Det ) - ( more + 2) this thed (24.0685+ Hm = Ps? V 2 eg 28 3.1122 249.87 +33) - ( Hi 4.215 9.81 + 1.7² +93762) 289151 t 0.364 72-88 Hm 55.844m conventing Him to perpsetne velocity in ampellen Hm Namp zg lear. 66. Vamp -33.1 m/sec sed 0.3 0.4 or 0.6 12 5 707. impeller diame for Dy? 5.84 08 1 Dyrehasre »HV, Q constant effricy line HOW a r350mm. 03 Di 1980 ♡ (m/w) Wom/ see 1986?wy *** fem p=18QHm 9.81 x B xoorxs.84 = 30.128 KW Ip=30.128kW
You can see any characteristic curve to reach to exact values.