ΧΟ Apply the Limit Comparison Test to the series Σ Vk3 + 2 4k3 + 3k2...
Use the Comparison Test to determine whether the series converges. 00 Σ 4k3+3 k= 1 The Comparison Test with Σ shows that the series k = 1
E) The series Σ-(-1)" 2- n a. converges conditionally. b. diverges by the nth term test. c. converges absolutely, d. converges by limit comparison test. F) The sum of the series 2-3)" is equal to e. None of the above E) The series Σ-(-1)" 2- n a. converges conditionally. b. diverges by the nth term test. c. converges absolutely, d. converges by limit comparison test. F) The sum of the series 2-3)" is equal to e. None of the above
Use the Limit Comparison Test to determine whether the series converges. The Limit Comparison Test with § 13K-3K) shows that the series diverges. k= 1 Consider the following convergent series. Complete parts a through c below. a. Use Sn to estimate the sum of the series. S2 (Round to seven decimal places as needed.) Determine how many terms of the following convergent series must be summed to be sure that the remainder is less than 10-in magnitude. (-1) k=0 (2k...
(1 point) Each of the following statements is an attempt to show that a given series is convergent or divergent using the Comparison Test (NOT the Limit Comparison Test.) For each statement, enter C (for "correct") if the argument is valid, or enter (for "incorrect") if any part of the argument is flawed. (Note: if the conclusion is true but the argument that led to it was wrong, you must enter l.) 1. For all n > 2, -16く흘, and...
(4) Let Σ ak and Σ bk be series with positive terms. The limit comparison test applies when a/bk L0; suppose for this problem that ak/bk0. (a) Show that if Σ bk converges, then Σ ak converges. Hint: remember we can delete finitely many terms from the series and not affect convergence. Use the fact a/bk0 to truncate the series at a convenient point. (b) Show that if ak diverges, then bk diverges. (c) Show by example that if Σ...
(1 point) Test each of the following series for convergence by either the Comparison Test or the Limit Comparison Test. If at least one test can be applied to the series, enter CONV if it converges or DIV if it diverges. If neither test can be applied to the series, enter NA. (Note: this means that even if you know a given series converges by some other test, but the comparison tests cannot be applied to it, then you must...
Use the Limit Comparison Test to determine the convergence or divergence of the series. 6 + 1 lim = L > 0 converges diverges Use the Limit Comparison Test to determine the convergence or divergence of the series. Στέ ο, Vn2 + 7 √2 + 7 lim - =L >0 n00 converges diverges -/2 POINTS LARCALCET6 9.4.016. Use the Limit Comparison Test to determine the convergence or divergence of the series. 61 + 1 70 + 1 6 7 +...
The series 61 - 1)*+1 20.8 diverges converges. k=1 Use the Limit Comparison Test to determine if the series converges. k? +9 k(k – 1)(k+2) k=1
In your answer state: (a) whether the above series Use the Limit Comparison Test to determine whether the following series is convergent or divergent Σ n +5 3 nin +4 is convergent or divergent, and (b) which series did you compare with the series is divergent, compare with E1 nin the series is convergent, compare with E 1 2. n=in the series is convergent, compare with E 1 nain the series is divergent, compare with 21 nin 1 the series...
Use the direct comparison test to test the series. 1. Use the direct comparison test to test the below series 3η 2. Σ-1 5. Σε πε5) ΠΟ = 4 η-1 10 α. Σ=2 τ