Question

SETUP the problem using the following teps - Part A De the way and agreed il vectors Since they have dons, there magnades en relevant. Be certain they have the correct orientations relative to the given coordinate system. The do in the center of the image represents the Non selected Press remove drawn elements Press to move to the next menu option Press CTRLV to get to the mention the cases to the application

Answer 1

and a Sol: According to the question, A particle with mass m= 1.81 x 10-3 kg charge of q = 1.22 x 10-8 C has, at a given instant, a velocity ze = (3.000 104 m/s) } . The streength of uniform magnetic field is, B = (1.637) Ê + (0.9807) ĵ So, direction of 3 is along ty direction. Direction of makes angle tant (0.980) = 31.01° with ta axis. an Part A Thus, Tec 31.01 the particle is, on Now, the force È que x - (1.22 X10-8 x3 x 104 ) x (1 637 +0.9801) N (3.66 8 10 4 7 ) × (1.63 î+0.9807) w = 11 3.66X10 N 1.63 0.980 ĥ Co- 1.63 x 3.66 x 10-4) N = = 1.63 x 3.66 x 10-4 k N

the acceleration vector of the Again, let ä be charge. So, Ž=0 ã= OR, 74 To T m OT) Ã m/s2 1.63 x 3.66 810-4 1.818 10-3 0.329 ote, m/s2 Part B: Theree force, The acceleration vectore of the charge à - 0.329 m/s²