Question

The number of hits to a Web site follows a Poisson process. Hits occur at the rate of 1.0 per minute between 7:00 P.M. and 12:00 P.M. Given below are three scenarios for the number of hits to the Web site. Compute the probability of each scenario between 9:10 P.M. and 9:13 P.M. and interpret the results. (a) exactly four hits (b) fewer than four hits (c) at least four hits (a) P(4) = (Round to four decimal places as needed.) Fill in the blanks to complete the statement below. On about of every 100 days, it is expected that there will be 9:10 P.M. and 9:13 P.M. exactly 4 hits to the Web site between (b) P(X<4)=(Round to four decimal places as needed.) Fill in the blanks to complete the statement below. On about of every 100 days, it is expected that there will be fewer than 4 hits to the Web site between 9:10 P.M. and 9:13 P.M. (c) P(X24)=(Round to four decimal places as needed.) Fill in the blanks to complete the statement below. at least 4 hits to the Web site between On about of every 100 days, it is expected that there will be 9:10 P.M. and 9:13 P.M.

Answer 1

It P3 expected that there cefil be Here we here that 0 Sol - at a) the . e 0.16803 It is probably distribution le P (2) (ht" X! then x = 0, 1, 2, 3, .... → Hits Occars out the rate of 10 per minule ☆ the probability of each scenario between 9: 10 pt4 & 90 13 pm And interpret the result 3 minutes probability Ps eycactly Your Plu) (1X3)":((x3) U! about 0.1680] of every 100 days, it Ps expected that thove will be excacite u hide to the web site between 9:10 pm to 9:13pm. b) probability PS fewer than four. (at)? .27 P (xcu) x? (3)% -3 E 7-0 a! Plo) +P12) 4P(3) on about [0.6172) of every 100 days, a is expected that there will be lfawer ton facil hats to the web site between Qilo PM to 9:13 pm c) probability at least four. P(x 28) 3 e 2-0 3 e 0.64723 -|- P(X28) -|- 0.6472 -0.3528 about 10.3598 of every 100 days, least u hits to the web site between 9:10 pm to 9:13PM.