Question

Water is pumped from a reservoir to a large receiver vessel which is maintained at p3 = 6 bar through the operation of the pu

In regards to question 3, will cavitation occur based on the NPSH available vs NPSH required?

NPSHR Taco MODEL 080622 TC/TS Series 75 100 125 1760 RPM March 25, 2019 175 200 225 Curve no. 2540 Min. Imp. Dia. 17.72 Size

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Given P₂ = 6 bar Kgv = 0.15 Ksy=2 Diameter of Ginch SCH 80 d d = 16.3mm = 0.1463m &= 0.05mm L = 135m Q- 0.15 ot/s Solution 0-h = total head loss. major loss + minor loss Above equation becomes 1 Pi Hp P4 (24-2, the sg eg .: Hpa (P4- Po) (26-2) + hl lThe relationship between the system head and the flow rate Hp = (P4 - P.) (24-2) + hi sg + 10+ Hp = (62109-1101325X101) (0.014) Checking for cavitation NPSHA = HA+Hs - Hf - Hup 2 HA - Atmospheric pressure head - 10,34m Hs= static head HE= head loss iQ(m3/s) Q (gpm) Hp (m) Hp (ft) 0 이 60.9352199.9186 0.031545 500 64.36217| 211.162 0.06309 1000 74.64307 244.892) 0.094635 150

NPSHR Taco seres MODEL 080622 TC/TS Series 75 100 125 FREQUIRED NPSH- 1760 RPM March 25, 2019 175 200 225 Curve no. 2540 Min.

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