Question

1 Determine the output for the following code: #include<stdio.h> int main static int num; fornum : ++ num: num++) -- printf("%d". num): if num ==8) break; [10] COI retum 1 b) #include<stdio.h> int main int test: fortest - 0: tests=5: test); printer test: retum

please help me asap

Answer 1

Here is the solution if you have any doubts then you can write in the comment section.

Please give feedback.

Solution:

(1)

static int num;
if we don't assign value to static then by default its value become 0;

Now we consider for loop:

for loop contains 4 steps in execution:

for(initialization;condition check;updation)

{

statement execution;

}

Step 1: initialization step execute.

Step 2: condition check, if condition true then repeat step 3 and 4

Step 3: statement execution

Step 4:updation(increment / decrement)

So we will find our output by using above 4 steps:

for(num++;++num;num++)

{
printf("%d",num);
if(num==8)
break;

}

step1: num++ now num=1

step2: ++num now num=2 it is true so we will repeat step 3 and 4

step3:

printf("%d",num); it will print 2

num != 8 so continue with loop

step 4: updation num++ now num=3

step 5: condition check ++num now num=4

step6:

printf("%d",num); it will print 4

num != 8 so continue with loop

step 7: updation num++ now num=5

step 8: condition check ++num now num=6

step9:

printf("%d",num); it will print 6

num != 8 so continue with loop

step 10: updation num++ now num=7

step 11: condition check ++num now num=8

step12:

printf("%d",num); it will print 8

here num==8 so break from loop

So final output will be:- 2 4 6 8

(2)

line 1: int test;

line 2: for(test=0;test<=5;test++);

line 3: printf("%d",test);

In line 1 a variable test is declared;

In line 2 a for loop is present; but loop is ended with a semicolon ( ; )

it means step 3 is missing according to our rules which I define above.

so for loop execution:

step 1: test=0;

step2: test<=5 true so repeat step 4 until it is true (step3 is not present according to our rules)

step3: nothing

step4: updation test++; so test=1;

step 5: test<=5 true so repeat

step 6: updation test++; so test=2;

step 7: test<=5 true so repeat

step 8: updation test++; so test=3;

step 9: test<=5 true so repeat

step 10: updation test++; so test=4;

step 11: test<=5 true so repeat

step 12: updation test++; so test=5;

step 13: test<=5 true so repeat

step 14: updation test++; so test=6;

step 15: test<=5 which is false now so break from for loop with test=6;

So now we will reach to line 3: printf("%d",test); so it will print 6

So final Output: 6

Thank You!